Files
MARTe-Integrated-Components/Client/udpscope/tests/FrameDecoderTest.cpp
T
Martino FerrariandClaude Opus 4.6 a2efc142c3 fix(udpscope): keep the accumulated-scalar timeline monotonic and bounded
Round 4 of Task 4 review. Four defects in FrameDecoder's rule 3:

- The undeclared-rate (hrt) path positioned each burst at an ABSOLUTE
  hrt/ticksPerSecond(). hrt counts from the producer's boot, so it is ~1e11
  ticks by the time a scope attaches, and the rate is refitted every packet
  with a few parts in 1e4 of wobble. The product is tens of milliseconds of
  jitter in BOTH directions -- not merely imprecise, non-monotonic. Integrate
  short tick deltas into accProdSec instead and let ClockOffset latch the
  epoch that leaves behind.
- The lead bleed used a fixed 0.9 factor, which converges only while the
  declared rate is within ~10%. Squeeze proportionally to the excess instead
  (floored at kMinBleedFactor), settling it in a single burst.
- A single-sample flush fell through to the plain-scalar rule, dating it from
  arrival and leaving lastCounter stale so the next real burst reinstated a
  hole that never existed. Accumulate mode flushes on a timer, so a short
  cycle legitimately yields one sample; keep it on the chain.
- kMaxCounterGap was inert: an absurd gap yields an absurd prediction that the
  arrival backstop already rejects, and no input can distinguish the two
  rules. Removed rather than left implying a behaviour it did not have.

FrameDecoder.h now states the deliberate divergence from StreamHub -- which
converts hrt with the LOCAL MARTe timer frequency, valid only because it runs
on the producer's host -- and why a remote scope's drift is irreducible.

Three new tests, each sabotage-proven non-vacuous: producer restart, short
flushes staying on the chain, and a 20000-packet undeclared run after a
day of producer uptime that asserts SPACING as well as ordering (the
monotonic guard alone restores order while leaving positions wrong).

Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
2026-08-27 22:16:11 +02:00

588 lines
23 KiB
C++

#include "FrameDecoder.h"
#include <gtest/gtest.h>
#include <vector>
using namespace udpscope;
namespace {
/** Builds a FrameView over vectors the test owns. */
struct FrameBuilder {
std::vector<std::vector<double>> storage;
std::vector<const double*> ptrs;
std::vector<uint32_t> counts;
FrameView view;
void addSignal(std::vector<double> vals) {
storage.push_back(std::move(vals));
}
/* Real frames carry a per-update counter; leaving it at zero would hide
* whichever rules depend on it, so it must be passed explicitly. */
const FrameView& build(uint64_t hrt, double recvTime, uint32_t numSamples = 1,
uint32_t counter = 0) {
ptrs.clear();
counts.clear();
for (const auto& s : storage) {
ptrs.push_back(s.data());
counts.push_back(static_cast<uint32_t>(s.size()));
}
view.counter = counter;
view.hrt = hrt;
view.recvTime = recvTime;
view.numSamples = numSamples;
view.numSignals = static_cast<uint32_t>(storage.size());
view.values = ptrs.data();
view.counts = counts.data();
return view;
}
};
SignalMeta burst(const char* name, uint8_t timeMode, double rate,
uint32_t elems, uint32_t timeIdx) {
SignalMeta m;
m.name = name;
m.typeCode = 8; /* float32 */
m.numRows = elems;
m.numCols = 1;
m.timeMode = timeMode;
m.samplingRate = rate;
m.timeSignalIdx = timeIdx;
return m;
}
SignalMeta timeSignal(const char* name, uint32_t elems) {
SignalMeta m;
m.name = name;
m.typeCode = 6; /* uint64 -> nanoseconds */
m.numRows = elems;
m.numCols = 1;
return m;
}
} /* namespace */
TEST(FrameDecoder, FullArrayTakesOneStampPerElementFromTheTimeSignal) {
FrameDecoder dec;
dec.setSignals({burst("Sine", kTimeFullArray, 1000.0, 4, 1),
timeSignal("Time", 4)});
FrameBuilder fb;
fb.addSignal({1.0, 2.0, 3.0, 4.0});
/* Nanoseconds: 5.000, 5.001, 5.002, 5.003 s of producer time. */
fb.addSignal({5.0e9, 5.001e9, 5.002e9, 5.003e9});
const FrameView& f = fb.build(0, 1000.0);
dec.beginFrame(f);
std::vector<double> ts;
ASSERT_TRUE(dec.timestamps(f, 0, ts));
ASSERT_EQ(ts.size(), 4u);
/* Element 0 lands on the arrival time; the rest keep the producer spacing. */
EXPECT_NEAR(ts[0], 1000.000, 1e-9);
EXPECT_NEAR(ts[1], 1000.001, 1e-9);
EXPECT_NEAR(ts[2], 1000.002, 1e-9);
EXPECT_NEAR(ts[3], 1000.003, 1e-9);
}
TEST(FrameDecoder, FirstSampleAnchorsElementZeroAndCountsForward) {
FrameDecoder dec;
dec.setSignals({burst("Sine", kTimeFirstSample, 1000.0, 4, 1),
timeSignal("Time", 1)});
FrameBuilder fb;
fb.addSignal({1.0, 2.0, 3.0, 4.0});
fb.addSignal({7.0e9});
const FrameView& f = fb.build(0, 2000.0);
dec.beginFrame(f);
std::vector<double> ts;
ASSERT_TRUE(dec.timestamps(f, 0, ts));
ASSERT_EQ(ts.size(), 4u);
EXPECT_NEAR(ts[0], 2000.000, 1e-9);
EXPECT_NEAR(ts[3], 2000.003, 1e-9);
}
TEST(FrameDecoder, LastSampleAnchorsTheFinalElementAndCountsBackward) {
FrameDecoder dec;
dec.setSignals({burst("Sine", kTimeLastSample, 1000.0, 4, 1),
timeSignal("Time", 1)});
FrameBuilder fb;
fb.addSignal({1.0, 2.0, 3.0, 4.0});
fb.addSignal({7.0e9});
const FrameView& f = fb.build(0, 3000.0);
dec.beginFrame(f);
std::vector<double> ts;
ASSERT_TRUE(dec.timestamps(f, 0, ts));
ASSERT_EQ(ts.size(), 4u);
EXPECT_NEAR(ts[3], 3000.000, 1e-9);
EXPECT_NEAR(ts[0], 3000.000 - 0.003, 1e-9);
}
TEST(FrameDecoder, PlainScalarUsesArrivalTime) {
FrameDecoder dec;
SignalMeta m;
m.name = "Level";
m.typeCode = 9;
dec.setSignals({m});
FrameBuilder fb;
fb.addSignal({42.0});
const FrameView& f = fb.build(0, 1234.5);
dec.beginFrame(f);
std::vector<double> ts;
ASSERT_TRUE(dec.timestamps(f, 0, ts));
ASSERT_EQ(ts.size(), 1u);
EXPECT_DOUBLE_EQ(ts[0], 1234.5);
}
// This is the failure UDPSourceSession.cpp:560 documents. The kernel delivers
// two queued datagrams microseconds apart even though each carries 10 ms of
// signal. Dating from arrival crams the second packet's samples into that gap
// and the trace becomes a sawtooth; dating from the producer hrt does not.
TEST(FrameDecoder, AccumulatedScalarSurvivesBurstyDelivery) {
FrameDecoder dec;
SignalMeta m;
m.name = "Acc";
m.typeCode = 9;
m.numRows = 1;
m.samplingRate = 1000.0; /* 1 kHz, 10 samples = 10 ms per packet */
dec.setSignals({m});
const double ticks = 1.0e9;
std::vector<double> all;
for (int p = 0; p < 40; p++) {
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, static_cast<double>(p)));
const double producerSec = 100.0 + p * 0.010;
/* Packets 20+ arrive in a burst, all within 50 us of each other. */
const double arrival = (p < 20) ? (500.0 + p * 0.010)
: (500.2 + (p - 20) * 0.00005);
const FrameView& f = fb.build(static_cast<uint64_t>(producerSec * ticks),
arrival, 10, static_cast<uint32_t>(p + 1));
dec.beginFrame(f);
std::vector<double> ts;
if (dec.timestamps(f, 0, ts)) {
all.insert(all.end(), ts.begin(), ts.end());
}
}
ASSERT_GT(all.size(), 300u);
for (size_t i = 1; i < all.size(); i++) {
EXPECT_GT(all[i], all[i - 1]) << "non-monotonic at " << i;
EXPECT_NEAR(all[i] - all[i - 1], 0.001, 2e-4)
<< "spacing collapsed at " << i << " (sawtooth)";
}
}
namespace {
/** Ten contiguous 10-sample bursts at 1 kHz, counters 1..10, ending at 500.090. */
SignalMeta accSignal() {
SignalMeta m;
m.name = "Acc";
m.typeCode = 9;
m.numRows = 1;
m.samplingRate = 1000.0; /* 10 samples = 10 ms per packet */
return m;
}
void primeTenBursts(FrameDecoder& dec, std::vector<double>& ts, bool withCounter) {
for (int p = 0; p < 10; p++) {
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& f = fb.build(0, 500.0 + p * 0.010, 10,
withCounter ? static_cast<uint32_t>(p + 1) : 0u);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts));
}
ASSERT_NEAR(ts[9], 500.090, 1e-9);
}
} /* namespace */
// The counterweight to the test above. Chaining bursts to suppress arrival
// jitter is only safe if loss is accounted for: a bare chain closes the hole a
// dropped datagram left and dates every later sample early for the rest of the
// run. The wire says exactly how much is missing, so no estimate is needed —
// and this test deliberately makes arrival time a LIAR (200 ms off) to prove
// the reconstruction comes from the counter and not from when the packet landed.
TEST(FrameDecoder, AccumulatedScalarReinstatesLostPacketsFromTheCounterGap) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/true);
/* Counter 111 after 10: 100 packets lost, 1000 samples, exactly 1 s. The
* packet lands 200 ms later than that truth would predict. */
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& f = fb.build(0, 501.300, 10, 111u);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts));
/* Chaining blindly gives 500.091; anchoring on arrival gives 501.291. */
EXPECT_NEAR(ts[0], 501.091, 1e-9);
EXPECT_NEAR(ts[9], 501.100, 1e-9);
}
// A producer that never advances the counter, or restarts it, leaves nothing to
// reconstruct from. Arrival time is then the better of two bad answers, and the
// chain has to be abandoned rather than left to drift forever.
TEST(FrameDecoder, AccumulatedScalarResyncsOnArrivalWhenTheCounterSaysNothing) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/false);
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& f = fb.build(0, 501.100, 10, 0u);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts));
EXPECT_NEAR(ts[0], 501.091, 1e-9);
EXPECT_NEAR(ts[9], 501.100, 1e-9);
}
// Re-anchoring must never move a signal's timestamps backwards: the ring, the
// trigger and the exporter all assume they increase, and a backward step is
// indistinguishable from corruption downstream. Here the counter claims a
// 20 s hole while the packet arrives 10 ms after the last one, so the
// prediction and arrival disagree wildly and arrival points into the past.
TEST(FrameDecoder, AccumulatedScalarNeverStepsBackwardsWhenResyncing) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/true);
const double prevEnd = ts[9];
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& f = fb.build(0, 500.000, 10, 2010u);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts));
/* Arrival (500.000) is behind our timeline, so there is nothing to spread
* into; the burst is squeezed instead, which bleeds the lead off while still
* moving strictly forwards. The excess (90 ms) is nine nominal burst widths,
* so the squeeze hits its floor of 0.05 and the step is 50 us. */
EXPECT_NEAR(ts[0], 500.09005, 1e-9);
EXPECT_GT(ts[0], prevEnd) << "resync stepped backwards over the previous burst";
for (size_t i = 1; i < ts.size(); i++) {
EXPECT_GT(ts[i], ts[i - 1]);
}
}
// When the chain has to be abandoned but arrival lies just ahead of where the
// last burst ended, the correction is made by COMPRESSING this one burst rather
// than by stepping back. Rejecting the correction instead would be one-directional
// — `predicted` is never below lastEmittedEnd + dt — and a timeline running fast
// could then never be pulled back.
TEST(FrameDecoder, AccumulatedScalarCompressesOneBurstRatherThanStepBack) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/true);
/* The compress branch needs the prediction to be rejected while arrival
* still sits between the previous burst's end and one burst beyond it —
* which a plain rate mismatch cannot produce, since the prediction is then
* only a burst away from arrival. It takes a fabricated loss: this gap
* claims 900000 lost packets, putting the prediction 2.5 hours out, while
* the packet itself lands 5 ms after the last burst ended so its arrival
* anchor (500.086) falls just behind that end. */
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& f = fb.build(0, 500.095, 10, 900011u);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts));
EXPECT_GT(ts[0], 500.090) << "compressed burst must still start after the last one";
EXPECT_NEAR(ts[9], 500.095, 1e-9) << "and end exactly on arrival";
EXPECT_NEAR(ts[1] - ts[0], 0.0005, 1e-9) << "spread over the available room";
}
// The whole point of compressing: a declared SamplingRate is a hand-written
// config value, and even a correct one is measured against the producer host's
// crystal, not ours. Tens of ppm of difference is certain over a long session,
// so the reconstructed timeline WILL run away from the wall clock. It has to be
// pulled back, and it has to stay monotonic while that happens.
TEST(FrameDecoder, AccumulatedScalarDoesNotDriftAwayFromTheWallClockForever) {
FrameDecoder dec;
dec.setSignals({accSignal()}); /* declares 1 kHz */
/* The producer really runs 1 % fast: 10 samples take 9.9 ms of wall time,
* so a chain stepping the declared 10 ms per packet gains 0.1 ms every
* packet. This is the direction re-anchoring alone cannot fix: arrival is
* always BEHIND the chain, so anchoring on it would step backwards and is
* refused. Only compression pulls the timeline back. */
double worstLead = 0.0;
double lastEnd = 0.0;
for (int p = 0; p < 20000; p++) {
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const double arrival = 500.0 + p * 0.0099;
const FrameView& f =
fb.build(0, arrival, 10, static_cast<uint32_t>(p + 1));
dec.beginFrame(f);
std::vector<double> ts;
ASSERT_TRUE(dec.timestamps(f, 0, ts));
for (size_t i = 0; i < ts.size(); i++) {
ASSERT_GT(ts[i], lastEnd) << "timeline went backwards at packet " << p;
lastEnd = ts[i];
}
worstLead = std::max(worstLead, ts[9] - arrival);
}
/* Unchecked, 20000 packets at 0.1 ms each would put the trace 2 s ahead. */
EXPECT_LT(worstLead, 0.6) << "timeline drifted " << worstLead << " s ahead";
}
// The C client de-duplicates fragments but not whole unfragmented updates, so a
// host subscribed on two interfaces sees each datagram twice. Emitting the
// repeat would double the values and advance time by a burst that never was.
TEST(FrameDecoder, AccumulatedScalarDropsADuplicatedDatagram) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/true);
const double endBefore = ts[9];
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& dup = fb.build(0, 500.1001, 10, 10u); /* counter 10 again */
dec.beginFrame(dup);
EXPECT_FALSE(dec.timestamps(dup, 0, ts));
/* And the drop must not have disturbed the chain: the genuine next packet
* still lands one period after burst 10 ended. */
const FrameView& next = fb.build(0, 500.109, 10, 11u);
dec.beginFrame(next);
ASSERT_TRUE(dec.timestamps(next, 0, ts));
EXPECT_NEAR(ts[0], endBefore + 0.001, 1e-9);
}
// A producer restart returns the counter to zero mid-stream. The unsigned gap
// then wraps to near 2^32; the loss it implies puts the chained prediction
// centuries out, the arrival backstop rejects it, and arrival becomes the only
// usable reference.
TEST(FrameDecoder, AccumulatedScalarSurvivesAProducerRestart) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/true);
const double prevEnd = ts[9];
/* Restarted producer: counter 1 again, and the outage lasted 3 s. */
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
const FrameView& f = fb.build(0, 503.100, 10, 1u);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts));
/* Reading the wrapped gap as a loss count would claim ~4.3e9 lost packets,
* some 5e8 seconds of fabricated signal. */
EXPECT_NEAR(ts[9], 503.100, 1e-9) << "restart must re-anchor on arrival";
EXPECT_GT(ts[0], prevEnd);
}
// Accumulate mode flushes on a timer, so a short cycle legitimately delivers a
// single sample between two full bursts. That packet must stay on the chain: if
// it fell through to the plain-scalar rule it would be dated from arrival while
// its neighbours are chained, and would leave lastCounter behind so the next
// real burst read the skip as a lost datagram.
TEST(FrameDecoder, AccumulatedScalarKeepsShortFlushesOnTheChain) {
FrameDecoder dec;
dec.setSignals({accSignal()});
std::vector<double> ts;
primeTenBursts(dec, ts, /*withCounter=*/true);
double last = ts[9];
uint32_t counter = 10u;
double arrival = 500.090;
for (int p = 0; p < 500; p++) {
/* Alternating 10-sample and 1-sample flushes, 10 ms and 1 ms of signal. */
const uint32_t n = (p % 2 == 0) ? 1u : 10u;
arrival += 0.001 * static_cast<double>(n);
FrameBuilder fb;
fb.addSignal(std::vector<double>(n, 1.0));
const FrameView& f = fb.build(0, arrival, n, ++counter);
dec.beginFrame(f);
ASSERT_TRUE(dec.timestamps(f, 0, ts)) << "short flush dropped at " << p;
ASSERT_EQ(ts.size(), n);
for (size_t i = 0; i < ts.size(); i++) {
ASSERT_GT(ts[i], last) << "timeline went backwards at packet " << p;
/* Contiguous: no phantom loss was ever reinstated. */
ASSERT_NEAR(ts[i] - last, 0.001, 1e-6) << "gap opened at packet " << p;
last = ts[i];
}
}
}
TEST(FrameDecoder, AccumulatedScalarDerivesDtFromTheHrtGapWhenNoRateIsDeclared) {
FrameDecoder dec;
SignalMeta m;
m.name = "Acc";
m.typeCode = 9;
m.samplingRate = 0.0; /* undeclared */
dec.setSignals({m});
const double ticks = 1.0e9;
std::vector<double> last;
for (int p = 0; p < 40; p++) {
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
/* 25 ms per packet, deliberately NOT 10: at 10 the expected 1 ms period
* equals kDefaultDt, so a decoder that never derived anything and just
* returned the default would pass a test named for the derivation. */
const double producerSec = 100.0 + p * 0.025;
/* Zero-mean arrival jitter, so the rate fit still converges but no
* single arrival GAP is right. Without it, uniform arrivals make
* packetBurst and the hrt path return the same number by construction
* and the test cannot tell which branch answered. */
const double jitter[4] = {0.0, 0.003, 0.0, -0.003};
const FrameView& f = fb.build(static_cast<uint64_t>(producerSec * ticks),
700.0 + p * 0.025 + jitter[p % 4], 10,
static_cast<uint32_t>(p + 1));
dec.beginFrame(f);
std::vector<double> ts;
if (dec.timestamps(f, 0, ts)) { last = ts; }
}
ASSERT_EQ(last.size(), 10u);
/* 25 ms of producer time across 10 samples is a 2.5 ms period, whatever the
* datagrams did on the way over. Arrival-spanning the last gap (22 ms)
* would give 2.2 ms; defaulting would give 1 ms. */
EXPECT_NEAR(last[1] - last[0], 0.0025, 2e-5);
}
// The trap the hrt path fell into once: positioning each burst at
// hrt / ticksPerSecond(). hrt counts from the PRODUCER'S BOOT, so it is already
// ~1e11 ticks for a machine that has been up a day, while the rate is refitted
// on every packet and wobbles by parts in 1e4 as arrival jitter enters and
// leaves the window. The wobble arrives multiplied by that whole epoch — tens of
// milliseconds, in both directions — so bursts land out of order. The producer
// clock here is EXACT; every timestamp inversion this test can see comes from
// the client's own arithmetic.
TEST(FrameDecoder, AccumulatedScalarStaysMonotonicOnALongUndeclaredRunAfterBoot) {
FrameDecoder dec;
SignalMeta m;
m.name = "Acc";
m.typeCode = 9;
m.samplingRate = 0.0; /* undeclared: the hrt path */
dec.setSignals({m});
const double ticks = 1.0e9;
const uint64_t bootHrt = static_cast<uint64_t>(86400.0 * ticks); /* up 1 day */
double last = 0.0;
uint32_t seed = 12345u;
for (int p = 0; p < 20000; p++) { /* 500 s of stream */
FrameBuilder fb;
fb.addSignal(std::vector<double>(10, 1.0));
/* Exact producer clock: 25 ms per packet, 2.5 ms per sample. */
const uint64_t hrt = bootHrt + static_cast<uint64_t>(p * 0.025 * ticks);
/* Ordinary scheduling jitter, +/- 1 ms, zero mean. */
seed = seed * 1103515245u + 12345u;
const double jitter = (static_cast<double>((seed >> 16) & 0xFFFFu) /
65535.0 - 0.5) * 0.002;
const FrameView& f = fb.build(hrt, 700.0 + p * 0.025 + jitter, 10,
static_cast<uint32_t>(p + 1));
dec.beginFrame(f);
std::vector<double> ts;
if (!dec.timestamps(f, 0, ts)) { continue; }
for (size_t i = 0; i < ts.size(); i++) {
ASSERT_GT(ts[i], last) << "timeline went backwards at packet " << p;
/* Ordering alone is too weak to pin this down: clamping a wrong
* absolute position to "just after the last one" restores the
* ordering while leaving the positions wrong, and every forward
* lurch is still accepted. The producer clock is exact, so the
* spacing must be exact too. */
if (p > 100) { /* past the fit warm-up and its packetBurst fallback */
ASSERT_NEAR(ts[i] - last, 0.0025, 1e-5)
<< "sample spacing wrong at packet " << p;
}
last = ts[i];
}
}
}
// A PACKET burst has no per-element time at all. Elements span
// (lastPacket, thisPacket] — backwards from arrival, because the samples were
// acquired before the packet landed. Forward extrapolation would let a jittered
// packet overlap the next one and break ring monotonicity.
TEST(FrameDecoder, PacketBurstDropsTheFirstFrameThenSpansBackwards) {
FrameDecoder dec;
dec.setSignals({burst("Raw", kTimePacket, 0.0, 5, kNoTimeSignal)});
FrameBuilder fb1;
fb1.addSignal({1.0, 2.0, 3.0, 4.0, 5.0});
const FrameView& f1 = fb1.build(0, 10.0);
dec.beginFrame(f1);
std::vector<double> ts;
EXPECT_FALSE(dec.timestamps(f1, 0, ts))
<< "the first packet has no previous arrival to span from";
FrameBuilder fb2;
fb2.addSignal({6.0, 7.0, 8.0, 9.0, 10.0});
const FrameView& f2 = fb2.build(0, 10.05);
dec.beginFrame(f2);
ASSERT_TRUE(dec.timestamps(f2, 0, ts));
ASSERT_EQ(ts.size(), 5u);
EXPECT_GT(ts[0], 10.0);
EXPECT_NEAR(ts[4], 10.05, 1e-12);
EXPECT_NEAR(ts[1] - ts[0], 0.01, 1e-12);
}
TEST(FrameDecoder, PacketBurstStaysMonotonicUnderJitteredArrivals) {
FrameDecoder dec;
dec.setSignals({burst("Raw", kTimePacket, 0.0, 8, kNoTimeSignal)});
const double jitter[] = {0.0, 0.004, -0.003, 0.006, -0.002, 0.0, 0.005, -0.004};
std::vector<double> all;
for (int p = 0; p < 8; p++) {
FrameBuilder fb;
fb.addSignal(std::vector<double>(8, 1.0));
const FrameView& f = fb.build(0, 20.0 + p * 0.05 + jitter[p]);
dec.beginFrame(f);
std::vector<double> ts;
if (dec.timestamps(f, 0, ts)) {
all.insert(all.end(), ts.begin(), ts.end());
}
}
ASSERT_GT(all.size(), 8u);
for (size_t i = 1; i < all.size(); i++) {
EXPECT_GT(all[i], all[i - 1]) << "packets overlapped at " << i;
}
}
TEST(FrameDecoder, ResetForgetsPerSignalHistory) {
FrameDecoder dec;
dec.setSignals({burst("Raw", kTimePacket, 0.0, 4, kNoTimeSignal)});
FrameBuilder fb;
fb.addSignal({1.0, 2.0, 3.0, 4.0});
const FrameView& f = fb.build(0, 5.0);
dec.beginFrame(f);
std::vector<double> ts;
EXPECT_FALSE(dec.timestamps(f, 0, ts));
const FrameView& f2 = fb.build(0, 5.1);
dec.beginFrame(f2);
EXPECT_TRUE(dec.timestamps(f2, 0, ts));
dec.reset();
const FrameView& f3 = fb.build(0, 5.2);
dec.beginFrame(f3);
EXPECT_FALSE(dec.timestamps(f3, 0, ts))
<< "after reset the next packet is again the first one";
}